第三次訓練——Secret Research
阿新 • • 發佈:2019-02-08
At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:
`positive result', `negative result', `experiment failed' or `experiment not completed'
The encrypted result constitutes a string of digits S, which may take one of the following forms:
positive result S = 1 or S = 4 or S = 78 negative result S = S35 experiment failed S = 9S4 experiment not completed S = 190S
(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)
You are to write a program which decrypts given sequences of digits.
Input
A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings. For each analysed sequence of digits the following lines should be sent to output (in separate lines):+ for a positive result - for a negative result * for a failed experiment ? for a not completed experiment
In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.
4 78 7835 19078 944
+ - ? *
#include <stdio.h>
#include <string.h>
int main()
{
int n,len,i,j,k;
char a[10000] = {'\0'};
scanf("%d",&n);
while(n--)
{
scanf("%s",a);
len = strlen(a);
if((len == 1) && ((a[0] == '1')||(a[0] == '4')))
printf("+\n");
else if((len == 2) && (a[0] == '7') && (a[1] == '8'))
printf("+\n");
else if((len >=2) && (a[len-2] == '3') && (a[len-1] == '5'))
printf("-\n");
else if((len >=3) && (a[0] == '1') && (a[1] == '9') && (a[2] == '0'))
printf("?\n");
else if((len >=2) && (a[0] == '9') && (a[len-1] == '4'))
printf("*\n");
}
return 0;
}