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hql語句中like查詢 對於 / ' " % 的處理

jdk1.5
public List searchByParas(String authId, String resourceId, Integer state,
			Integer value, String description) {
		log.debug("finding KiiUaResAuth instance by example");
		try {
			description = description.replace("//", "//////").replace("%", "//%").replace("'", "''");
			StringBuffer hql = new StringBuffer(
					"from KiiUaResAuth as k join k.id.resource as r where k.description like '%"
							+ description + "%'");
			if (authId != "") {
				hql.append(" and k.id.authId='" + authId + "'");
			}
			if (resourceId != "") {
				hql.append(" and r.resourceId='" + resourceId + "'");
			}
			if (state != null) {
				hql.append(" and k.resAuthState=" + state);
			}
			if (value != null) {
				hql.append(" and k.value=" + value);
			}
			if (description.indexOf("//") >= 0) {
				hql.append(" escape '/'");
			}
			List results = getHibernateTemplate().find(hql.toString());
			log.debug("find by example successful, result size: "
					+ results.size());
			List toresult = new ArrayList();
			Object[] objlist = null;
			if (results.size() != 0) {
				for (int i = 0; i < results.size(); i++) {
					Object objs = results.get(i);
					objlist = (Object[]) objs;
					if (objlist[0] != null) {
						toresult.add((KiiUaResAuth) objlist[0]);
					}
				}
			}
			return toresult;
		} catch (RuntimeException re) {
			log.error("find by example failed", re);
			throw new SystemException("UA1202");
		}
	}