十六進位制加法 C和C++
阿新 • • 發佈：2019-02-20
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input +A -A +1A 12 1A -9 -1A -12 1A -AA
Sample Output 0 2C 11 -2C -90
using namespace std;
int main()
{
long long a,b,c;
while(cin>>hex>>a>>b)
{
c=a+b;
if(c>=0)
cout << setiosflags(ios::uppercase)<<hex<<c<<endl;
else
{
c=-c;
cout <<"-"<<setiosflags(ios::uppercase)<<hex <<c<<endl;
}
}
return 0;
}
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input +A -A +1A 12 1A -9 -1A -12 1A -AA
Sample Output 0 2C 11 -2C -90
#include<iostream>
using namespace std;
int main()
{
long long a,b,c;
while(cin>>hex>>a>>b)
{
c=a+b;
if(c>=0)
cout << setiosflags(ios::uppercase)<<hex<<c<<endl;
else
{
c=-c;
cout <<"-"<<setiosflags(ios::uppercase)<<hex <<c<<endl;
}
}
return 0;
}
利用庫了函式iomanip，