java + httpclient +post請求(記錄下)
阿新 • • 發佈:2019-04-01
服務 ati -type eth catch xxxxxxxx name util eat public void testMethodpost(){
//初始化http請求
CloseableHttpClient httpclient=HttpClientBuilder.create().build();
String url = "xxxxxxxxxxxxx";
//初始化http請求
HttpPost post=new HttpPost(url);
//設置請求頭
post.setHeader("Content-Type","application/json;charset=UTF-8");
try {
//初始化http請求
CloseableHttpClient httpclient=HttpClientBuilder.create().build();
String url = "xxxxxxxxxxxxx";
//初始化http請求
HttpPost post=new HttpPost(url);
//設置請求頭
post.setHeader("Content-Type","application/json;charset=UTF-8");
try {
String paramJson="{\"userName\":\"xxxxxxx\",\"passWord\":\"JVGK+jDLU7\"}";
// JSONObject jsonObject = JSON.parseObject(paramJson);
//
// System.out.println(jsonObject);
// String param=JSON.toJSONString(jsonObject);
// 提交參數發送請求 StringEntity requestEntity = new StringEntity(paramJson,"UTF-8"); post.setEntity(requestEntity); CloseableHttpResponse response=httpclient.execute(post); HttpEntity entity=response.getEntity(); String entityStr =EntityUtils.toString(entity,"UTF-8"); System.out.println(entityStr); //httpclient.close(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } 遇到的坑: 1.前期使用POST數據時,用了UrlEncodedFormEntity()這個方法 結果服務器返回500,打印的請求參數為:key=value&key2=value2格式 解決辦法:使用 StringEntity requestEntity = new StringEntity(paramJson,"UTF-8");辦法解決
java + httpclient +post請求(記錄下)