Python之雙色球選購和三級菜單問題
# 1 雙色球（假設一共八個球，6個紅球，球號1-32、2個藍球，球號1-16）
# 2 確保用戶不能重復選擇，不能超出範圍
# 3 用戶輸入有誤時有相應的錯誤提示
# 4 最後展示用戶選擇的雙色球的號碼
select_red_ball = []
while True:
n = int(input(‘請輸入你要選擇的紅色球(1-32)：‘))
if 0 < n < 33:
if n not in select_red_ball:
select_red_ball.append(n)
else:
print(‘number %d is already exist in red ball list‘ % n)
else:
print(‘only can select n between 1-32‘)
if len(select_red_ball) == 6:
break
select_red_ball.sort()
select_blue_ball = []
while True:
n = int(input(‘請輸入你要選擇的藍色球(1-32)：‘))
if 0 < n < 17:
if n not in select_blue_ball:
select_blue_ball.append(n)
else:
print(‘number %d is already exist in blue ball list‘ % n)
else:
print(‘only can select n between 1-16‘)
if len(select_blue_ball) == 2:
break
select_blue_ball.sort()
print(‘red ball %d‘ % select_red_ball)
print(‘blue ball %d‘ % select_blue_ball)
2 ：三級菜單
-
數據結構： menu = { ‘北京‘:{ ‘海澱‘:{ ‘五道口‘:{ ‘soho‘:{}, ‘網易‘:{}, ‘google‘:{} }, ‘中關村‘:{ ‘愛奇藝‘:{}, ‘汽車之家‘:{}, ‘youku‘:{}, }, ‘上地‘:{ ‘百度‘:{}, }, }, ‘昌平‘:{ ‘沙河‘:{ ‘老男孩‘:{}, ‘北航‘:{}, }, ‘天通苑‘:{}, ‘回龍觀‘:{}, }, ‘朝陽‘:{}, ‘東城‘:{}, }, ‘上海‘:{ ‘閔行‘:{ "人民廣場":{ ‘炸雞店‘:{} } }, ‘閘北‘:{ ‘火車站‘:{ ‘攜程‘:{} } }, ‘浦東‘:{}, }, ‘山東‘:{}, } 需求： 可依次選擇進入各子菜單 可從任意一層往回退到上一層 可從任意一層退出程序 所需新知識點：列表、字典
代碼一：
exit_flag = False
while not exit_flag:
for i in menu:
print(i)
choice1 = input("選擇進入1>>:")
if choice1 in menu:
while not exit_flag:
for i2 in menu[choice1]:
print("\t", i2)
choice2 = input("選擇進入2>>:")
if choice2 in menu[choice1]:
while not exit_flag:
for i3 in menu[choice1][choice2]:
print("\t\t", i3)
choice3 = input("選擇進入3>>:")
if choice3 in menu[choice1][choice2]:
for i4 in menu[choice1][choice2][choice3]:
print("\t\t", i4)
choice4 = input("最後一層，按b返回>>:")
if choice4 == "b":
pass
elif choice4 == "q":
exit_flag = True
if choice3 == "b":
break
elif choice3 == "q":
exit_flag = True
if choice2 == "b":
break
elif choice2 == "q":
exit_flag = True
代碼二：（優化版本，代碼縮減為15行）
current_layer = menu
parent_layer = [] # 將父級key值放入到列表中
flags = False # 設置標誌位
while not flags:
for key in current_layer:
print(key)
choose = input("請選擇，輸入b返回上一級菜單，輸入q退出菜單:").strip() # 去除空格
if choose in current_layer:
parent_layer.append(current_layer) # 將當前的狀態放入列表中
current_layer = current_layer[choose]
elif choose == ‘b‘:
if parent_layer:
current_layer = parent_layer.pop()
elif choose == ‘q‘:
flags = True
else:
print(‘輸入有誤，請重新輸入‘)
Python之雙色球選購和三級菜單問題