Java上傳大文件
阿新 • • 發佈：2017-06-07
error dsi ktr word nbsp comment buffer bytes part
看了日誌，錯誤為：
| 1 |
java.lang.OutOfMemoryError Java heap space
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上傳文件代碼如下：
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public static String uploadSingleFile(String path,MultipartFile file) {
if (!file.isEmpty()) {
byte[] bytes;
try {
bytes = file.getBytes();
// Create the file on server
File serverFile = createServerFile(path,file.getOriginalFilename());
BufferedOutputStream stream = new BufferedOutputStream(
new FileOutputStream(serverFile));
stream.write(bytes); stream.flush();
stream.close();
logger.info("Server File Location="
+ serverFile.getAbsolutePath());
return getRelativePathFromUploadDir(serverFile).replaceAll("\\\\", "/");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
System.out.println(e.getMessage());
}
}else{
System.out.println("文件內容為空");
}
return null;
}
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乍一看沒什麽大問題，我在 stream.write(bytes); 這句加了斷點，發覺根本就沒走到。而是在 bytes = file.getBytes(); 就報錯了。
原因應該是文件太大的話，字節數超過Integer（Bytes[]數組）的最大值，導致的問題。
既然這樣，把文件一點點的讀進來即可。
修改上傳代碼如下：
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public static String uploadSingleFile(String path,MultipartFile file) {
if (!file.isEmpty()) {
//byte[] bytes;
try {
//bytes = file.getBytes();
// Create the file on server
File serverFile = createServerFile(path,file.getOriginalFilename());
BufferedOutputStream stream = new BufferedOutputStream(
new FileOutputStream(serverFile));
int length=0;
byte[] buffer = new byte[1024];
InputStream inputStream = file.getInputStream();
while ((length = inputStream.read(buffer)) != -1) {
stream.write(buffer, 0, length);
}
//stream.write(bytes);
stream.flush();
stream.close();
logger.info("Server File Location="
+ serverFile.getAbsolutePath());
return getRelativePathFromUploadDir(serverFile).replaceAll("\\\\", "/");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
System.out.println(e.getMessage());
}
}else{
System.out.println("文件內容為空");
}
return null;
}
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轉自http://www.2cto.com/kf/201702/596396.html
Java上傳大文件