題目鏈接：https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=13&page=show_problem&problem=1041

LCS類型的題，不過並不是找common character，而是common word.就先把string處理成a list of word，然後再用LCS算法求common word。

代碼如下：

  1 #include <iostream>
  2 #include <math.h>
  3 #include <stdio.h>
  4
 
 #include <cstdio>
  5 #include <algorithm>
  6 #include <string.h>
  7 #include <cstring>
  8 #include <queue>
  9 #include <vector>
 10 #include <functional>
 11 #include <cmath>
 12 #define SCF(a) scanf("%d", &a)
 13 #define IN(a) cin>>a
 14
 
 #define FOR(i, a, b) for(int i=a;i<b;i++)
 15 typedef long long Int;
 16 using namespace std;
 17 
 18 int main()
 19 {
 20     char str1[1005], str2[1005];
 21     vector<string> v1, v2;
 22     int testCase = 1;
 23     int len1 = 0, len2 = 0;
 24     while (cin.getline(str1, 1005))
 25     {
 26
 
         cin.getline(str2, 1005);
 27         int cnum = 0;
 28         char word[25];
 29         string wd;
 30         len1 = 0;
 31         len2 = 0;
 32         for (int i = 0; str1[i] != ‘\0‘; i++)
 33         {
 34             len1++;
 35             if ((str1[i] >= ‘a‘ && str1[i] <= ‘z‘) || (str1[i] >= ‘A‘ && str1[i] >= ‘Z‘) || (str1[i] >= ‘0‘ && str1[i] <= ‘9‘))
 36             {
 37                 word[cnum++] = str1[i];
 38             }
 39             else
 40             {
 41                 if (cnum > 0)
 42                 {
 43                     word[cnum++] = ‘\0‘;
 44                     wd = string(word);
 45                     v1.push_back(wd);
 46                 }
 47                 cnum = 0;
 48             }
 49         }
 50         if (cnum > 0)
 51         {
 52             word[cnum++] = ‘\0‘;
 53             wd = string(word);
 54             v1.push_back(wd);
 55         }
 56         cnum = 0;
 57         for (int i = 0; str2[i] != ‘\0‘; i++)
 58         {
 59             len2++;
 60             if ((str2[i] >= ‘a‘ && str2[i] <= ‘z‘) || (str2[i] >= ‘A‘ && str2[i] >= ‘Z‘) || (str2[i] >= ‘0‘ && str2[i] <= ‘9‘))
 61             {
 62                 word[cnum++] = str2[i];
 63             }
 64             else
 65             {
 66                 if (cnum > 0)
 67                 {
 68                     word[cnum++] = ‘\0‘;
 69                     wd = string(word);
 70                     v2.push_back(wd);
 71                 }
 72                 cnum = 0;
 73             }
 74         }
 75         if (cnum > 0)
 76         {
 77             word[cnum++] = ‘\0‘;
 78             wd = string(word);
 79             v2.push_back(wd);
 80         }
 81 
 82         int **match = new int*[v1.size() + 1];
 83         FOR(i, 0, v1.size() + 1)
 84             match[i] = new int[v2.size() + 1];
 85 
 86         FOR(i, 0, v1.size() + 1)
 87             match[i][0] = 0;
 88         FOR(i, 0, v2.size() + 1)
 89             match[0][i] = 0;
 90 
 91         FOR(i, 1, v1.size() + 1)
 92         {
 93             FOR(j, 1, v2.size() + 1)
 94             {
 95                 if (v1[i - 1] == v2[j - 1])
 96                     match[i][j] = match[i - 1][j - 1] + 1;
 97                 else
 98                     match[i][j] = max(match[i - 1][j], match[i][j - 1]);
 99             }
100         }
101         if(len1==0 || len2==0)
102             printf("%2d. Blank!\n", testCase++);
103         else
104             printf("%2d. Length of longest match: %d\n", testCase++, match[v1.size()][v2.size()]);
105 
106         while (!v1.empty())
107             v1.pop_back();
108         while (!v2.empty())
109             v2.pop_back();
110 
111         FOR(i, 0, v1.size() + 1)
112             delete[] match[i];
113         delete[] match;
114 
115     }
116     return 0;
117 }

UVA 10100 Longest Match