pad algo ont pop ack stat des sub tdi

D - The War Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%lld & %llu Submit Status

Description

A war had broken out because a sheep from your kingdom ate some grasses which belong to your neighboring kingdom. The counselor of your kingdom had to get prepared for this war. There are N

(1 <= N <= 2500) unarmed soldier in your kingdom and there are M (1 <= M <= 40000) weapons in your arsenal. Each weapon has a weight W (1 <= W <= 1000), and for soldier i, he can only arm the weapon whose weight is between minWi and maxWi ( 1 <= minWi <= maxWi <= 1000). More armed soldier means higher success rate of this war, so the counselor wants to know the maximal armed soldier he can get, can you help him to win this war?

Input

There multiple test cases. The first line of each case are two integers N, M. Then the following N lines, each line contain two integers minWi, maxWi for each soldier. Next M lines, each line contain one integer W represents the weight of each weapon.

Output

For each case, output one integer represents the maximal number of armed soldier you can get.

Sample Input

3 3
1 5
3 7
5 10
4
8
9
2 2
5 10
10 20
4
21

Sample Output

2
0

貪心的問題，人能夠使用的有一些範圍，武器有重量，唯一要解決的問題就是在一個人的控制範圍內包括還有一個人的，這樣的情況要讓範圍小的先找

y有小到大，假設y同樣時x由小到大。

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
struct node{
    int x , y ;
} p[2600];
int q[1200] ;
bool cmp(node a,node b)
{
    return a.y < b.y || ( a.y == b.y && a.x < b.x ) ;
}
int main()
{
    int i , j , n , m ;
    while(scanf("%d %d", &n, &m) !=EOF )
    {
        memset(q,0,sizeof(q));
        for(i = 0 ; i < n ; i++)
            scanf("%d %d", &p[i].x, &p[i].y);
        while(m--)
        {
            scanf("%d", &i);
            q[i]++ ;
        }
        m = 0 ;
        sort(p,p+n,cmp);
        for(i = 0 ; i < n ; i++)
        {
            int l = p[i].x , r = p[i].y ;
            for(j = l ; j <= r ; j++)
                if( q[j] )
            {
                q[j]--;
                m++ ;
                break;
            }
        }
        printf("%d\n", m);
    }
    return 0 ;
}

測試賽D - The War（有控制範圍的貪心）