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luogu p3371 單源最短路徑(dijkstral

air gre continue size 手寫 with include syn bits

本來我寫的對的

我就多手寫了個

ios::sync_with_stdio(false);

我程序裏面用了cin 還有scanf 本來想偷偷懶

我就說 我查了半天錯 根本找不到的啊...

後來交了幾次 發現一直有RE 才發現...... 我好笨

//最短路 dijkstral
#include<bits/stdc++.h>
using namespace std;
typedef long long  ll;
const int maxn = 10010;
const ll INF = 2147483647;
typedef pair<ll ,int> pli;
struct node { int to,cost; node(int t,int c):to(t),cost(c){} bool operator < (const node & a)const { return cost > a.cost; } }; vector<node> E[maxn]; ll d[maxn]; priority_queue<pli,vector<pli>,greater<pli> > Q; int main() {
int n,m,st; cin>> n>>m>>st; for(int i=1;i<=m;i++) { int x,y,v; scanf("%d %d %d",&x, &y ,&v); E[x].push_back({y,v}); } for(int i=1;i<=n;i++) { d[i]=INF; } d[st] = 0; Q.push({0,st});
while ( Q.size() ) { pli now = Q.top();Q.pop(); ll cost = now.first; int p=now.second; if(cost >= INF) continue; for(int i=0;i<E[p].size();i++) { int v = E[p][i].to; if(d[v] > cost + E[p][i].cost) { d[v] = cost + E[p][i].cost;//更新最短路; Q.push({d[v],v}); } } } for(int i=1;i<=n;i++) { if(i!= n) cout<<d[i]<<" "; else cout<<d[i]; } cout<<endl; }

luogu p3371 單源最短路徑(dijkstral