解決思路：

1. 棧

2.使用Map，判斷是否

 public boolean isValid(String s) {
        Stack<Character> parens = new Stack<>();
        
        Map<Character, Character> parenMap = new HashMap<>();
        parenMap.put(‘(‘, ‘)‘);
        parenMap.put(‘[‘, ‘]‘);
        parenMap.put(‘{‘, ‘}‘);
        
        
        
 
for (int i = 0; i < s.length(); i++) {
            char paren = s.charAt(i);
            boolean isLeft = parenMap.containsKey(paren);
            
            
        
            if (isLeft) {
                parens.push(paren);
            } else {
                if (parens.empty()) {
                    
 
return false;
                }

                char leftSide = parens.pop();
                if (parenMap.get(leftSide) != paren) {
                    return false;
                }
                
            
            }
        }
        
        return parens.empty();
    }

匹配

Valid Parentheses(括號匹配）