案例1-合並2個不同文件夾中的csv文件到另外一個目錄,相同的文件名進行數據合並,不同的文件名直接移到新文件夾
阿新 • • 發佈:2018-02-27
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發現在ubuntu和centos中有些命令還不一樣,比如<<<可在centos中使用,但是ubuntu中不行
方法1,可在ubuntu和centos中使用
#!/bin/bash filenum=30 dir1=./upload_root/gdby dir2=./upload_root/bzbygz dir_merge=./download #刪除舊文件 rm -f $dir_merge/*.csv dir1_select=`ls $dir1 | sort -r | head -$filenum` dir2_select=`ls $dir2 | sort -r | head -$filenum` #2個文件夾共有的 echo "兩個學校共有的文件名" for i in ${dir1_select} do for file2 in ${dir2_select} do if [ "$i" = "$file2" ];then echo $i num1=$(head -1 $dir1/$i | awk -F "," ‘{print $2}‘) num2=$(head -1 $dir2/$i | awk -F "," ‘{print $2}‘) money1=$(head -1 $dir1/$i | awk -F "," ‘{print $4}‘) money2=$(head -1 $dir2/$i | awk -F "," ‘{print $4}‘) num_all=$(($num1+$num2)) money_all=$(echo $money1 $money2 | awk ‘{print $1+$2}‘) cp $dir1/$i $dir_merge sed -ie "1 s#`echo $num1`#`echo $num_all`#; 1 s#`echo $money1`#`echo $money_all`#" $dir_merge/$i #sed ‘1d‘ $dir2/$i >> $dir_merge/$i tail -n +2 $dir2/$i >> $dir_merge/$i fi done done rm -f $dir_merge/*.csve #只在$dir1中有的: echo "只在gdby中存在的文件" for i in ${dir1_select} do for file2 in ${dir2_select} do if [ "$i" != "$file2" ];then cp $dir1/$i $dir_merge fi done done #grep -q $i <<< ${dir2_select};if [[ $? -ne 0 ]];then cp $dir1/$i $dir_merge;fi;done #只在$dir2中有的: echo "只在bzbygz存在的文件" for i in ${dir2_select} do for file1 in ${dir1_select} do if [ "$i" != "$file1" ];then cp $dir2/$i $dir_merge fi done done
方法2,只能在centos中使用
#!/bin/bash filenum=30 dir1=./test1 dir2=./test2 dir_merge=./test3 #刪除舊文件 rm -f $dir_merge/*.csv dir1_select=`ls $dir1 | sort -r | head -$filenum` dir2_select=`ls $dir2 | sort -r | head -$filenum` #2個文件夾共有的 for i in ${dir1_select} do grep -q $i <<< ${dir2_select} #<<<只能在centos中使用, grep -q安靜模式,不打印任何標準輸出。如果有匹配的內容則立即返回狀態值0。if [[ $? -eq 0 ]];then echo $i num1=$(head -1 $dir1/$i | awk -F "," ‘{print $2}‘) num2=$(head -1 $dir2/$i | awk -F "," ‘{print $2}‘) money1=$(head -1 $dir1/$i | awk -F "," ‘{print $4}‘) money2=$(head -1 $dir2/$i | awk -F "," ‘{print $4}‘) num_all=$(($num1+$num2)) money_all=$(echo $money1 $money2 | awk ‘{print $1+$2}‘) cp $dir1/$i $dir_merge sed -ie "1 s#`echo $num1`#`echo $num_all`#; 1 s#`echo $money1`#`echo $money_all`#" $dir_merge/$i #sed ‘1d‘ $dir2/$i >> $dir_merge/$i tail -n +2 $dir2/$i >> $dir_merge/$i fi done rm -f $dir_merge/*.csve #只在$dir1中有的: for i in ${dir1_select};do grep -q $i <<< ${dir2_select};if [[ $? -ne 0 ]];then cp $dir1/$i $dir_merge;fi;done #只在$dir2中有的: for i in ${dir2_select};do grep -q $i <<< ${dir1_select};if [[ $? -ne 0 ]];then cp $dir2/$i $dir_merge;fi;done
案例1-合並2個不同文件夾中的csv文件到另外一個目錄,相同的文件名進行數據合並,不同的文件名直接移到新文件夾