ZS the Coder loves to read the dictionary. He thinks that a word is nice if there exists asubstring (contiguous segment of letters) of it of length 26 where each letter of English alphabet appears exactly once. In particular, if the string has length strictly less than 26, no such substring exists and thus it is not nice.

Now, ZS the Coder tells you a word, where some of its letters are missing as he forgot them. He wants to determine if it is possible to fill in the missing letters so that the resulting word is nice. If it is possible, he needs you to find an example of such a word as well. Can you help him?

Input

The first and only line of the input contains a single string s

Output

If there is no way to replace all the question marks with uppercase letters such that the resulting word is nice, then print ?-?1 in the only line.

Otherwise, print a string which denotes a possible nice word that ZS the Coder learned. This string should match the string from the input, except for the question marks replaced with uppercase English letters.

If there are multiple solutions, you may print any of them.

Example

ABC??FGHIJK???OPQR?TUVWXY?

ABCDEFGHIJKLMNOPQRZTUVWXYS

WELCOMETOCODEFORCESROUNDTHREEHUNDREDANDSEVENTYTWO

-1

??????????????????????????

MNBVCXZLKJHGFDSAQPWOEIRUYT

AABCDEFGHIJKLMNOPQRSTUVW??M

-1

Note

In the first sample case,ABCDEFGHIJKLMNOPQRZTUVWXYS is a valid answer beacuse it contains a substring of length 26 (the whole string in this case) which contains all the letters of the English alphabet exactly once. Note that there are many possible solutions, such as ABCDEFGHIJKLMNOPQRSTUVWXYZ orABCEDFGHIJKLMNOPQRZTUVWXYS.

In the second sample case, there are no missing letters. In addition, the given string does not have a substring of length 26 that contains all the letters of the alphabet, so the answer is ?-?1.

In the third sample case, any string of length 26that contains all letters of the English alphabet fits as an answer.

題目巴拉巴拉很多 有用的信息不多

題意：給你一個字符串 有沒有一個有著連續的長度為26的字串，它包含所有的26個字母

這題就是純暴力，從第 i 個字符開始搜索看看i+26 符不符合條件

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<queue>
 6 using namespace std;
 7 char a[50010];
 8 int b[30];
 9 int main() {
10     while(scanf("%s",a)!=EOF) {
11         int n=strlen(a),flag1,flag2=0;
12         if (n<26) {
13             printf("-1\n");
14             continue;
15         }
16         for (int i=0 ; i<n-25 ; i++ ) {
17             flag1=1;
18             memset(b,0,sizeof(b));
19             for (int j=i ; j<i+26 ; j++) {
20                 if (a[j]>=‘A‘ && a[j]<=‘Z‘) {
21                     b[a[j]-‘A‘]++;
22                 }
23                 if  (b[a[j]-‘A‘]>=2) {
24                     flag1=0;
25                     break;
26                 }
27             }
28             if (!flag1) continue;
29             flag2=1;
30             for (int j=i ; j<i+26 ; j++) {
31                 if (a[j]==‘?‘) {
32                     for (int k=0 ; k<26 ; k++) {
33                         if (b[k]==0) {
34                             a[j]=k+‘A‘;
35                             b[k]=1;
36                             break;
37                         }
38                     }
39                 }
40             }
41             if (flag2) break;
42         }
43         if (flag2) {
44             for (int i=0 ;i<n ;i++){
45                 if (a[i]==‘?‘) printf("A");
46                 else printf("%c",a[i]);
47             }
48             printf("\n");
49         }else printf("-1\n");
50     }
51     return 0;
52 }

Complete the Word CodeForces - 716B