原文在這裏，寫的很詳細，感謝原作者，以下摘錄要點。

itertools用於高效循環的叠代函數集合。

無限叠代器

1 叠代器         參數         結果                                                例子
2 count()     start, [step]   start, start+step, start+2*step, ...                count(10) --> 10 11 12 13 14 ...
3 cycle()     p               p0, p1, ... plast, p0, p1, ...                      cycle(‘
 
ABCD‘) --> A B C D A B C D ...
4 repeat()    elem [,n]       elem, elem, elem, ... endlessly or up to n times    repeat(10, 3) --> 10 10 10

處理輸入序列叠代器

 1 叠代器          參數            結果                                        例子
 2 chain()     p, q, ...           p0, p1, ... plast, q0, q1, ...              chain(‘
 
ABC‘, ‘DEF‘) --> A B C D E F
 3 compress()  data, selectors     (d[0] if s[0]), (d[1] if s[1]), ...         compress(‘ABCDEF‘, [1,0,1,0,1,1]) --> A C E F
 4 dropwhile() pred, seq           seq[n], seq[n+1], starting when pred fails  dropwhile(lambda x: x<5, [1,4,6,4,1]) --> 6 4 1
 5 groupby()   iterable[, keyfunc] sub-iterators grouped by value of keyfunc(v)
 
 6 ifilter()   pred, seq           elements of seq where pred(elem) is True    ifilter(lambda x: x%2, range(10)) --> 1 3 5 7 9
 7 ifilterfalse()  pred, seq       elements of seq where pred(elem) is False   ifilterfalse(lambda x: x%2, range(10)) --> 0 2 4 6 8
 8 islice()    seq, [start,] stop [, step] elements from seq[start:stop:step]  islice(‘ABCDEFG‘, 2, None) --> C D E F G
 9 imap()      func, p, q, ...     func(p0, q0), func(p1, q1), ...             imap(pow, (2,3,10), (5,2,3)) --> 32 9 1000
10 starmap()   func, seq           func(*seq[0]), func(*seq[1]), ...           starmap(pow, [(2,5), (3,2), (10,3)]) --> 32 9 1000
11 tee()       it, n               it1, it2 , ... itn splits one iterator into n
12 takewhile() pred, seq           seq[0], seq[1], until pred fails            takewhile(lambda x: x<5, [1,4,6,4,1]) --> 1 4
13 izip()      p, q, ...           (p[0], q[0]), (p[1], q[1]), ...             izip(‘ABCD‘, ‘xy‘) --> Ax By
14 izip_longest()  p, q, ...       (p[0], q[0]), (p[1], q[1]), ...             izip_longest(‘ABCD‘, ‘xy‘, fillvalue=‘-‘) --> Ax By C- D-

組合生成器

1 叠代器          參數                        結果
2 product()       p, q, ... [repeat=1]        cartesian product, equivalent to a nested for-loop
3 permutations()  p[, r]                      r-length tuples, all possible orderings, no repeated elements
4 combinations()  p, r                        r-length tuples, in sorted order, no repeated elements
5 combinations_with_replacement() p, r        r-length tuples, in sorted order, with repeated elements
6 product(‘ABCD‘, repeat=2)                   AA AB AC AD BA BB BC BD CA CB CC CD DA DB DC DD
7 permutations(‘ABCD‘, 2)                     AB AC AD BA BC BD CA CB CD DA DB DC
8 combinations(‘ABCD‘, 2)                     AB AC AD BC BD CD
9 combinations_with_replacement(‘ABCD‘, 2)    AA AB AC AD BB BC BD CC CD DD

[轉載] Python itertools模塊詳解