python 獲取兩個dict的差異
阿新 • • 發佈：2018-11-02
參考文件：
https://stackoverflow.com/questions/1165352/calculate-difference-in-keys-contained-in-two-python-dictionaries
class DiffDict(object):
"""獲取兩個dict的差異"""
def __init__(self, current, last): self.current = current self.last = last self.set_current = set(current) self.set_last = set(last) self.intersect_keys = self.set_current & self.set_last
def get_added(self): """current - 交集 = 新增的key""" added_keys = self.set_current - self.intersect_keys return [{'key': key, 'value': self.current.get(key)} for key in added_keys]
def get_removed(self): """last - 交集 = 減去的key""" removed_keys = self.set_last - self.intersect_keys return [{'key': key, 'value': self.current.get(key)} for key in removed_keys]
def get_changed(self): """用交集中的key去兩個dict中找出值不相等的""" changed_keys = set(o for o in self.intersect_keys if self.current.get(o) != self.last.get(o)) return [{ 'key': key, 'value': '%s -> %s' % (self.last.get(key), self.current.get(key)) } for key in changed_keys]
def __init__(self, current, last): self.current = current self.last = last self.set_current = set(current) self.set_last = set(last) self.intersect_keys = self.set_current & self.set_last
def get_added(self): """current - 交集 = 新增的key""" added_keys = self.set_current - self.intersect_keys return [{'key': key, 'value': self.current.get(key)} for key in added_keys]
def get_removed(self): """last - 交集 = 減去的key""" removed_keys = self.set_last - self.intersect_keys return [{'key': key, 'value': self.current.get(key)} for key in removed_keys]
def get_changed(self): """用交集中的key去兩個dict中找出值不相等的""" changed_keys = set(o for o in self.intersect_keys if self.current.get(o) != self.last.get(o)) return [{ 'key': key, 'value': '%s -> %s' % (self.last.get(key), self.current.get(key)) } for key in changed_keys]