leetcode 926. Flip String to Monotone Increasing
給定一個由 0 和 1 組成的序列 A ,問至少翻轉多少個 0 和 1 使得該序列前部分都是 0 後部分都是 1.
思路:列舉0和1的分界點,代價可以O(1)的算出來,只需要預處理出序列A中一開始有幾個0即可,代價就是當前掃過的1的個數加上後面的0的個數
class Solution { public: int minFlipsMonoIncr(string S) { int len = S.length(); int zoro=0,one=0; for(int i = 0; i < len; i++){ if(S[i]=='0') zoro++; } int ans = min(9999999,one+zoro); for(int i = 0; i <len; i++) { if(S[i]=='0') zoro--; else one++; ans=min(ans,zoro+one); } return ans; } };
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