SQL SERVER 資料匯出JSON
原文:https://www.cnblogs.com/hank-chen/p/5916929.html
執行下面的儲存過程:
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE[dbo].[SerializeJSON](
@ParameterSQL AS VARCHAR(MAX)
)
AS
BEGIN
DECLARE @SQL NVARCHAR(MAX)
DECLARE @XMLString VARCHAR(MAX)
DECLARE @XML XML
DECLARE @Paramlist NVARCHAR(1000)
SET @Paramlist = N
'@XML XML OUTPUT'
SET @SQL =
'WITH PrepareTable (XMLString)'
SET @SQL = @SQL +
'AS('
SET @SQL = @SQL + @ParameterSQL+
'FOR XML RAW,TYPE,ELEMENTS'
SET @SQL = @SQL +
')'
SET @SQL = @SQL +
'SELECT @XML=[XMLString]FROM[PrepareTable]'
EXEC sp_executesql @SQL, @Paramlist, @[email protected] OUTPUT
SET @XMLString=CAST(@XML AS VARCHAR(MAX))
DECLARE @JSON VARCHAR(MAX)
DECLARE @Row VARCHAR(MAX)
DECLARE @RowStart INT
DECLARE @RowEnd INT
DECLARE @FieldStart INT
DECLARE @FieldEnd INT
DECLARE @KEY VARCHAR(MAX)
DECLARE @Value VARCHAR(MAX)
DECLARE @StartRoot VARCHAR(100);SET @StartRoot=
'<row>'
DECLARE @EndRoot VARCHAR(100);SET @EndRoot=
'</row>'
DECLARE @StartField VARCHAR(100);SET @StartField=
'<'
DECLARE @EndField VARCHAR(100);SET @EndField=
'>'
SET @RowStart=CharIndex(@StartRoot,@XMLString,0)
SET @JSON=
''
WHILE @RowStart>0
BEGIN
SET @[email protected]+Len(@StartRoot)
SET @RowEnd=CharIndex(@EndRoot,@XMLString,@RowStart)
SET @Row=SubString(@XMLString,@RowStart,@[email protected])
SET @[email protected]+
'{'
-- for each row
SET @FieldStart=CharIndex(@StartField,@Row,0)
WHILE @FieldStart>0
BEGIN
-- parse node key
SET @[email protected]+Len(@StartField)
SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
SET @KEY=SubString(@Row,@FieldStart,@[email protected])
SET @[email protected]+
'"'[email protected]+'":'
-- parse node value
SET @[email protected]+1
SET @FieldEnd=CharIndex(
'</',@Row,@FieldStart)
SET @Value=SubString(@Row,@FieldStart,@[email protected])
SET @[email protected]+
'"'[email protected]+'",'
SET @[email protected]+Len(@StartField)
SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
SET @FieldStart=CharIndex(@StartField,@Row,@FieldEnd)
END
IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))
SET @[email protected]+
'},'
--/ for each row
SET @RowStart=CharIndex(@StartRoot,@XMLString,@RowEnd)
END
IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))
SET @JSON=
'['[email protected]+']'
SELECT @JSON
END
GO
執行下面的指令碼就能生成JSON格式資料
EXEC[SerializeJSON] 'SELECT * FROM [dbo].[TEST]'