LeetCode-225-Implement Stack using Queues-M(用佇列實現堆疊)
阿新 • • 發佈:2018-12-11
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack(); stack.push(1); stack.push(2); stack.top(); // returns 2 stack.pop(); // returns 2 stack.empty(); // returns false
Notes:
- You must use only standard operations of a queue – which means only push to back, peek/pop from front, size, and is empty operations are valid.
- Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
class MyStack { private: queue<int> q; int size; public: MyStack() { size=0; } /** Push element x onto stack. */ void push(int x) { if(q.size() == 0) { q.push(x); } else { q.push(x); for(int i=0; i<size; i++) { q.push(q.front()); q.pop(); } } size++; } /** Removes the element on top of the stack and returns that element. */ int pop() { int ret = q.front(); q.pop(); return ret; } /** Get the top element. */ int top() { return q.front(); } /** Returns whether the stack is empty. */ bool empty() { return q.size() == 0; } };