leetcode (Longest Uncommon Subsequence I)
Title:Longest Uncommon Subsequence I 521
Difficulty:Easy
原題leetcode地址:https://leetcode.com/problems/longest-uncommon-subsequence-i/
1. 註解見程式碼註釋
時間複雜度:O(1)。
空間複雜度:O(1),沒有申請額外空間。
/** * a和b一樣,則返回-1;a和b的長度誰大,返回誰的長度,否則返回a的長度 * @param a * @param b * @return */ public static int findLUSlength(String a, String b) { int aLen = a.length(); int bLen = b.length(); if (aLen != bLen) { return Math.max(aLen, bLen); } if (a == b) { return -1; } return aLen; }
相關推薦
leetcode (Longest Uncommon Subsequence I)
Title:Longest Uncommon Subsequence I 521 Difficulty:Easy 原題leetcode地址:https://leetcode.com/problems/longest-uncommon-sub
C#LeetCode刷題之#521-最長特殊序列 Ⅰ(Longest Uncommon Subsequence I)
問題 給定兩個字串,你需要從這兩個字串中找出最長的特殊序列。最長特殊序列定義如下:該序列為某字串獨有的最長子序列(即不能是其他字串的子序列)。 子序列可以通過刪去字串中的某些字元實現,但不能改變剩餘字元的相對順序。空序列為所有字串的子序列,任何字串為其自身的子序列。 輸入為兩個字串,
LeetCode:521. Longest Uncommon Subsequence I(找出特殊的子字串)
Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. The longest uncommo
LeetCode: 521 Longest Uncommon Subsequence I(easy)
via gin easy some ges 不同 rem hat chan 題目: anysubsequence of the other strings. A subsequence is a sequence that can be derived from one s
[LeetCode] Longest Uncommon Subsequence I 最長非共同子序列之一
Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. The longest uncommon subsequence is defined
521. Longest Uncommon Subsequence I【easy】
str efi cau () appear som delet pear empty 521. Longest Uncommon Subsequence I【easy】 Given a group of two strings, you need to find the
521. Longest Uncommon Subsequence I
sub cau one note cte 字符串 rac amp 字符串長度 Given a group of two strings, you need to find the longest uncommon subsequence of this group of t
*521. Longest Uncommon Subsequence I (bit manipulation 2^n)
comm bec delet without inpu tin character emp BE Given a group of two strings, you need to find the longest uncommon subsequence of this
[LeetCode] 522. Longest Uncommon Subsequence II
ott longest pre order vat 特殊字符串 lean bool you Given a list of strings, you need to find the longest uncommon subsequence among them.
leetcode (Maximum Average Subarray I)
Title:Maximum Average Subarray I 643 Difficulty:Easy 原題leetcode地址:https://leetcode.com/problems/maximum-average-subarray-i/  
leetcode (Student Attendance Record I)
Title:Student Attendance Record I 551 Difficulty:Easy 原題leetcode地址:https://leetcode.com/problems/student-attendance-record-i/
[LeetCode]522. Longest Uncommon Subsequence II
給一組字串,找出最長不相同子序列(子序列是保證相對位置不變,子字串是保證相鄰且順序不變),如果不存在就返回-1 找出所有字串的所有子序列,然後找裡面滿足要求的 public class Solution { public int findLUSlength(S
#Leetcode# 522. Longest Uncommon Subsequence II
without cdc als http them nbsp any amp itself https://leetcode.com/problems/longest-uncommon-subsequence-ii/ Given a list of strings,
LeetCode 300. 最長上升子序列(Longest Increasing Subsequence)
輸出 pan 因此 需要 ack 時間復雜度 family class 一個數 題目描述 給出一個無序的整形數組,找到最長上升子序列的長度。 例如, 給出 [10, 9, 2, 5, 3, 7, 101, 18], 最長的上升子序列是 [2, 3, 7, 101],
leetcode (Longest Continuous Increasing Subsequence)
Title:Longest Continuous Increasing Subsequence 674 Difficulty:Easy 原題leetcode地址:https://leetcode.com/problems/longest-continuous-i
【LeetCode】Longest Common Subsequence最長公共子序列(求出某一解+LCS長度)
Longest Common Subsequence 給出兩個字串,找到最長公共子序列(LCS),返回LCS的長度。 說明 最長公共子序列的定義: • 最長公共子序列問題是在一組序列(通常2個)中找到最長公共子序列(注意:不同於子串,LCS不需要是
【python3】leetcode 594. Longest Harmonious Subsequence(easy)
594. Longest Harmonious Subsequence(easy) We define a harmonious array is an array where the difference between its maximum value and its mini
最長遞增子序列O(NlogN)演算法(leetcode 300. Longest Increasing Subsequence )
最長遞增子序列,Longest Increasing Subsequence 下面我們簡記為 LIS。排序+LCS演算法 以及 DP演算法就忽略了,這兩個太容易理解了。假設存在一個序列d[1..9] = 2 1 5 3 6 4 8 9 7,可以看出來它的LIS長度為5。下面
C#LeetCode刷題之#551-學生出勤紀錄 I(Student Attendance Record I)
問題 給定一個字串來代表一個學生的出勤紀錄,這個紀錄僅包含以下三個字元: 'A' : Absent,缺勤 'L' : Late,遲到 'P' : Present,到場 如果一個學生的出勤紀錄中不超過一個'A'(缺勤)並且不超過兩個連續的'L'(遲到),那麼這個學生會被獎賞。 你需要根
C#LeetCode刷題之#551-學生出勤紀錄 I(Student Attendance Record I)
問題 給定一個字串來代表一個學生的出勤紀錄,這個紀錄僅包含以下三個字元: 'A' : Absent,缺勤 'L' : Late,遲到 'P' : Present,到場 如果一個學生的出勤紀錄中不超過一個'A'(缺勤)並且不超過兩個連續的'L'(遲到),那麼這個學生會被獎賞