我的程式碼

 public static void main(String[] args) {
        String str = "we are family's";
        StringBuffer sb = new StringBuffer(str).reverse();
        String[] split = sb.toString().split(" ");
        sb = new StringBuffer();
        for (int i = 0;i<split.length;i++){
            sb.append(split
 
[split.length-1-i]).append(" ");
        }
        System.out.println(sb.toString());
    }

別人的程式碼：
1. 簡單解決方案

public class Solution {
    public String reverseWords(String s) {
        String words[] = s.split(" ");
        StringBuilder res=new StringBuilder();
        for (String word: words)
            res.append(new
 
 StringBuffer(word).reverse().toString() + " ");
        return res.toString().trim();
    }
}

原理一樣，沒什麼亮點。

public class Solution {
    public String reverseWords(String s) {
        String words[] = split(s);
        StringBuilder res=new StringBuilder();
        for (String word: words)
            res.append(reverse(word) + " "
 
);
        return res.toString().trim();
    }
    public String[] split(String s) {
        ArrayList < String > words = new ArrayList < > ();
        StringBuilder word = new StringBuilder();
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == ' ') {
                words.add(word.toString());
                word = new StringBuilder();
            } else
                word.append( s.charAt(i));
        }
        words.add(word.toString());
        return words.toArray(new String[words.size()]);
    }
    public String reverse(String s) {
      StringBuilder res=new StringBuilder();
        for (int i = 0; i < s.length(); i++)
            res.insert(0,s.charAt(i));
        return res.toString();
    }
}

可以效率高，但程式碼太冗餘了。