1002 A+B for Polynomials （25 分）

This time, you are supposed to find A+B where A and B are two polynomials.

Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:

K N1 a​N1N​2aN​2 … N​Ka​N​K
​​
​​

where K is the number of nonzero terms in the polynomial, N​i and a​N​i(i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10，0≤N​K<⋯<N2<N1≤1000.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input:

2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output:

3 2 1.5 1 2.9 0 3.2

//我剛開始以為指數也可以為小數……編了一大通，提交上去一堆錯
//結果是，指數必為整數，係數必為一位小數

#include <cstdio>
#include <cstring>
#include <cmath>

double coe[1001] = { 0 };//多項式儲存，下標為指數，儲存資料為係數

int main()
{
	int n = 0, m = 0, cnt = 0, i = 0;//cnt為多項式個數
	int exp = 0;
	double t_coe = 0;
	scanf("%d", &n);
	for (i = 0; i < n; i++
 
)
	{
		scanf("%d %lf", &exp, &t_coe);
		coe[exp] += t_coe;
	}
	scanf("%d", &m);
	for (i = 0; i < m; i++)
	{
		scanf("%d %lf", &exp, &t_coe);
		coe[exp] += t_coe;
	}
	i = 0;
	while (i <= 1000) if (coe[i++]) cnt++;//統計多項式的個數
	printf("%d", cnt);
	for (int i = 1000; i>=0; i--) 
	   if (coe[i]) 
	      printf(" %d %.1lf", i, coe[i]);//逆序列印，格式為保留一位小數
	return 0;
}