YAML的Java實現——JYAML基本原理與示例（3）YAML對檔案流的處理
阿新 • • 發佈：2019-01-06
請您先閱讀：
1. FileOutputStream
以流的方式，將資料寫入到YAML檔案中。
/* Output data structure into a YAML file as a FileOutputStream. */ try { YamlEncoder yEncoder = new YamlEncoder(new FileOutputStream(dumpFile)); for (int i = 0; i < 3; ++i) { michael.setAge(24 + i); yEncoder.writeObject(michael); yEncoder.flush(); } } catch (FileNotFoundException e) { e.printStackTrace(); }
2. FileInputStream
以流的方式，從YAML檔案中將資料讀入。
/* Input a YAML file into data structure as a FileOutputStream. */ try { YamlDecoder yDecoder = new YamlDecoder(new FileInputStream(dumpFile)); Person[] persons = {new Person(), new Person(), new Person()}; for (int i = 0; i < 3; ++i) { persons[i] = (Person) yDecoder.readObject(); System.out.println(); TestYaml.output(persons[i]); } } catch (FileNotFoundException e) { e.printStackTrace(); } catch (EOFException e) { e.printStackTrace(); }
3. 檢視YAML檔案
--- &0 !com.sinosuperman.yaml.Person age: 24 children: &2 !com.sinosuperman.yaml.Person[] - !com.sinosuperman.yaml.Person age: 3 name: boy - !com.sinosuperman.yaml.Person age: 1 name: girl name: Michael Corleone spouse: !com.sinosuperman.yaml.Person age: 24 children: *2 name: Floveria Edie spouse: *0 --- &9 !com.sinosuperman.yaml.Person age: 25 children: &11 !com.sinosuperman.yaml.Person[] - !com.sinosuperman.yaml.Person age: 3 name: boy - !com.sinosuperman.yaml.Person age: 1 name: girl name: Michael Corleone spouse: !com.sinosuperman.yaml.Person age: 24 children: *11 name: Floveria Edie spouse: *9 --- &18 !com.sinosuperman.yaml.Person age: 26 children: &20 !com.sinosuperman.yaml.Person[] - !com.sinosuperman.yaml.Person age: 3 name: boy - !com.sinosuperman.yaml.Person age: 1 name: girl name: Michael Corleone spouse: !com.sinosuperman.yaml.Person age: 24 children: *20 name: Floveria Edie spouse: *18