題幹：

There is a number N.You should output "YES" if N is a multiple of 2, 3 or 5,otherwise output "NO".

Input

There are multiple test cases, no more than 1000 cases. 
For each case,the line contains a integer N.(0<N<1030)(0<N<1030)

Output

For each test case,output the answer in a line.

Sample Input

2
3
5
7

Sample Output

YES
YES
YES
NO

解題報告：

    水題啊。判斷是否是2,3,5的倍數。

AC程式碼：

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream> 
#define ll long long
using namespace std;
char s[100005];
int main()
{
	while(~scanf("%s",s+1)) {
		int len = strlen(s+1);
		ll sum = 0;
		for(int i = 1; i<=len; i++) {
			sum += s[i] - '0';
		}
		if(sum%3==0 || (s[len] - '0') %2 == 0 || (s[len] - '0' == 5)) puts("YES");
		else puts("NO");
		
	}
	return 0 ;
 }