6、

CREATE TABLE`employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

題目描述

查詢所有員工入職時候的薪水情況，給出emp_no以及salary，並按照emp_no進行逆序selecte.emp_no,s.salary

from employeese,salaries s

where e.emp_no = s.emp_no and e.hire_date =s.from_date

order by e.emp_no desc;

7、

CREATE TABLE`salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

題目描述

查詢薪水漲幅超過15次的員工號emp_no以及其對應的漲幅次數t
selectemp_no,count(emp_no) as t

from salaries

group by emp_no having t>=15;

7、題目描述

找出所有員工當前(to_date='9999-01-01')具體的薪水salary情況，對於相同的薪水只顯示一次,並按照逆序顯示
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

輸入描述:

select distinct salary

fromsalaries

where to_date='9999-01-01'

order by salary desc;

8、題目描述

獲取所有部門當前manager的當前薪水情況，給出dept_no, emp_no以及salary，當前表示to_date='9999-01-01'
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

輸入描述:

select d.dept_no,d.emp_no,s.salary

fromsalaries s

join dept_manager d

on s.emp_no = d.emp_no

andd.to_date = '9999-01-01'

ands.to_date = '9999-01-01'

9、

獲取所有非manager的員工emp_no
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

輸入描述:

select e.emp_no

fromemployees e

where e.emp_no not in (select emp_no fromdept_manager);

10、

題目描述

獲取所有員工當前的manager，如果當前的manager是自己的話結果不顯示，當前表示to_date='9999-01-01'。結果第一列給出當前員工的emp_no,第二列給出其manager對應的manager_no。
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));

輸入描述:

select de.emp_no,dm.emp_no as manager_no

fromdept_emp de ,dept_manager dm

where de.dept_no = dm.dept_no

and de.emp_no != dm.emp_no

and de.to_date = '9999-01-01'

and dm.to_date = '9999-01-01';

或

select e.emp_no, m.emp_no as manager_no from dept_empe join dept_manager m

on e.dept_no = m.dept_no

where e.emp_no != m.emp_no

and e.to_date = '9999-01-01'

and m.to_date = '9999-01-01';