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python闖關3——國際象棋問題

題幹

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Almost everyone in the world knows about the ancient game Chess and has at least a basic understanding of its rules. It has various units with a wide range of movement patterns allowing for a huge number of possible different game positions (for example Number of possible chess games at the end of the n-th plies.) For this mission, we will examine the movements and behavior of chess pawns.

Chess is a two-player strategy game played on a checkered game board laid out in eight rows (called ranks and denoted with numbers 1 to 8) and eight columns (called files and denoted with letters a to h) of squares. Each square of the chessboard is identified by a unique coordinate pair — a letter and a number (ex, “a1”, “h8”, “d6”). For this mission we only need to concern ourselves with pawns. A pawn may capture an opponent’s piece on a square diagonally in front of it on an adjacent file, by moving to that square. For white pawns the front squares are squares with greater row than their.

A pawn is generally a weak unit, but we have 8 of them which we can use to build a pawn defense wall. With this strategy, one pawn defends the others. A pawn is safe if another pawn can capture a unit on that square. We have several white pawns on the chess board and only white pawns. You should design your code to find how many pawns are safe.
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pawns

You are given a set of square coordinates where we have placed white pawns. You should count how many pawns are safe.

Input: Placed pawns coordinates as a set of strings.

Output: The number of safe pawns as a integer.

Example:

safe_pawns({“b4”, “d4”, “f4”, “c3”, “e3”, “g5”, “d2”}) == 6

safe_pawns({“b4”, “c4”, “d4”, “e4”, “f4”, “g4”, “e5”}) == 1

How it is used: For a game AI one of the important tasks is the ability to estimate game state. This concept will show how you can do this on the simple chess figures positions.

Precondition:
0 < pawns ≤ 8

我的程式碼

def safe_pawns(pawns):
    answer = 0
    for pawn in pawns :
        if chr(ord(pawn[0])-1)+str(int(pawn[1])-1) in pawns or chr(ord(pawn[0])+1)+str(int(pawn[1])-1) in pawns : answer +=1
    return answer

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

總結

ord函式:找到字母的ascii碼
chr():ascii轉為字元