leetcode由易入難——【4】Decode Ways
阿新 • • 發佈:2019-01-24
(12).
A message containing letters from A-Z
is being encoded to numbers using the following mapping:
'A' -> 1
'B' -> 2
...
'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.
For example,
Given encoded message "12"
, it could be decoded as "AB"
(1 2) or
"L"
The number of ways decoding "12"
is 2.
分析:該題與Climbing Stairs 類似,只是多了幾條判斷語句。
// LeetCode, Decode Ways // 動態規劃,時間複雜度O(n),空間複雜度O(1) class Solution { public: int numDecodings(const string s) { if (s.empty() || s[0] == '0') return 0; int prev = 0; int cur = 1; // 長度為n的字串,有n+1個階梯 for (size_t i = 1; i <= s.size(); ++i) { if (s[i-1] == '0') cur = 0; if (i < 2 || !(s[i - 2] == '1' || (s[i - 2] == '2' && s[i - 1] <= '6'))) //當i < 2 或者 i 超過 1~26 的範圍,將重置prev. prev = 0; int tmp = cur; cur = prev + cur; prev = tmp; } return cur; } };