[C++] LeetCode 17. 電話號碼的字母組合
阿新 • • 發佈:2019-01-26
題目
給定一個數字字串,返回數字所有可能表示的字母組合。
下面給出數字到字母的對映(和電話號碼一樣)。
輸入:數字字串 “23”
輸出:[“ad”, “ae”, “af”, “bd”, “be”, “bf”, “cd”, “ce”, “cf”].
說明:
儘管上面的答案是按字典序排列的,但是你的答案可以是任何順序。
程式碼
class Solution {
public:
vector<string> letterCombinations(string digits) {
vector<string> s1,s2;
map <char,vector<string>> mp;
mp['2']={"a","b","c"};
mp['3']={"d","e","f"};
mp['4']={"g","h","i"};
mp['5']={"j","k","l"};
mp['6']={"m","n","o"};
mp['7']={"p","q","r","s"};
mp['8']={"t","u","v"};
mp['9']={"w","x","y","z"};
for (auto &ch:digits){
int size=s1.size();
auto &v=mp[ch];
for(auto &s:v){
for(int i=0;i<size;i++){
string tmp=s1[i]+s;
s2.push_back(tmp);
}
if(size==0) s2.push_back(s);
}
swap(s1,s2);
s2.clear();
}
return s1;
}
};