1. 程式人生 > >[C++] LeetCode 17. 電話號碼的字母組合

[C++] LeetCode 17. 電話號碼的字母組合

題目

給定一個數字字串,返回數字所有可能表示的字母組合。
下面給出數字到字母的對映(和電話號碼一樣)。
這裡寫圖片描述
輸入:數字字串 “23”
輸出:[“ad”, “ae”, “af”, “bd”, “be”, “bf”, “cd”, “ce”, “cf”].

說明:
儘管上面的答案是按字典序排列的,但是你的答案可以是任何順序。

程式碼

class Solution {
public:
    vector<string> letterCombinations(string digits) {
        vector<string> s1,s2;
        map
<char,vector<string>>
mp; mp['2']={"a","b","c"}; mp['3']={"d","e","f"}; mp['4']={"g","h","i"}; mp['5']={"j","k","l"}; mp['6']={"m","n","o"}; mp['7']={"p","q","r","s"}; mp['8']={"t","u","v"}; mp['9']={"w","x","y","z"}; for
(auto &ch:digits){ int size=s1.size(); auto &v=mp[ch]; for(auto &s:v){ for(int i=0;i<size;i++){ string tmp=s1[i]+s; s2.push_back(tmp); } if(size==0) s2.push_back(s); } swap(s1,s2); s2.clear(); } return
s1; } };

提交結果

這裡寫圖片描述