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分治法求最大最小元

#include<iostream>
using namespace std;
int fmax(int a, int b) {
	return (a > b) ? a : b;
}
int fmin(int a, int b) {
	return(a < b) ? a : b;
}
void maxmin(int *l, int &max, int &min, int a, int b) {
	int x1, y1, x2, y2;
	int mid;
	if (b-a <= 1) {
		if (l[a]>l[b]) {
			min = l[b];
			max = l[a];
		}
		else {
			max = l[b];
			min = l[a];
		}
	}
	else{
		mid = (a + b) / 2;
		maxmin(l, x1, y1, a, mid);
		maxmin(l, x2, y2, mid + 1, b);
		max = fmax(x1, x2);
		min = fmin(y1, y2);
	}
}
int main() {
	int l[10];
	int max, min;
	for (int i = 0; i < 10; i++)
		cin >> l[i];
	maxmin(l, max, min, 0, 9);
	cout << max << " "<<min << endl;
	return 0;
}