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SDNU 1539 Do you like Hot Dog ?

acm NPU element out mat prev items end ostream

Description

Hot dog is a very delicious food,and Goc like it very much. The picture below shows how much does Goc like it. hhhhh... 技術分享圖片 Given a set of hot dog, each with a price and a happy value , determine a way to choose the items into a knapsack so that the total price is less than or equal to a given limit ? and the total happy value is as large as possible. Find the maximum total happy value. (Note that each item can be only chosen once).

Input

The first line contains the integer ? indicating to the number of test cases.

For each test case, the first line contains the integers ? and ?.

Following ? lines provide the information of each item.

The line contains the price and the happy value of the ? item respectively.

?

All the inputs are integers.

Output

For each test case, output the maximum value.

Sample Input

1
5 15
12 4
2 2
1 1
4 10
1 2

Sample Output

15
#include <cstdio>
#include <iostream>
#include <queue>
#include <cstring>
#include <string>
#include <cmath>
using namespace std;
#define
ll long long int t, n, pri, p[500+8], v[500+8], dp[500+8][5000+8], sum; void solve() { fill(dp[0], dp[0] + 5005, 0x3f3f3f3f); dp[0][0] = 0; for(int i = 0; i<n; i++) { for(int j = 0; j <= 5001; j++) { if(j<v[i]) dp[i+1][j] = dp[i][j]; else dp[i+1][j] = min(dp[i][j],dp[i][j-v[i]]+p[i]); } } int miao = 0; for(int i = 0; i <= 5001; i++) { if(dp[n][i] <= pri) miao = i; } printf("%d\n", miao); } int main() { scanf("%d", &t); memset(dp, 0, sizeof(dp)); memset(p, 0, sizeof(p)); memset(v, 0, sizeof(v)); while(t--) { scanf("%d%d", &n, &pri); for(int i = 0; i<n; i++) { scanf("%d%d", &p[i], &v[i]); } solve(); } return 0; }

SDNU 1539 Do you like Hot Dog ?