Python中的排序函式argsort,sort,sorted用法
阿新 • • 發佈:2019-02-01
argsort()函式
<span style="font-size:18px;">>>> x = np.array([3, 1, 2]) >>> np.argsort(x) #按升序排列 array([1, 2, 0]) >>> np.argsort(-x) #按降序排列 array([0, 2, 1]) >>> x[np.argsort(x)] #通過索引值排序後的陣列 array([1, 2, 3]) >>> x[np.argsort(-x)] array([3, 2, 1]) 另一種方式實現按降序排序: >>> a = x[np.argsort(x)] >>> a array([1, 2, 3]) >>> a[::-1] array([3, 2, 1]) </span>
sort()函式和sorted()函式
sort函式是list列表中的函式,而sorted可以對list或者iterator進行排序
1、用sort函式對列表排序時會影響列表本身,而sorted不會
>>> a = [1,2,1,4,3,5]
>>> a.sort()
>>> a
[1, 1, 2, 3, 4, 5]
>>> a = [1,2,1,4,3,5]
>>> sorted(a)
[1, 1, 2, 3, 4, 5]
>>> a
[1, 2, 1, 4, 3, 5]
2、
(2)用key函式排序<span style="white-space:pre"> </span>>>> list1 = [('david', 90), ('mary',90), ('sara',80),('lily',95)] >>> sorted(list1,cmp = lambda x,y: cmp(x[0],y[0])) [('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)] >>> sorted(list1,cmp = lambda x,y: cmp(x[1],y[1])) [('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
<span style="white-space:pre"> </span>>>> list1 = [('david', 90), ('mary',90), ('sara',80),('lily',95)]
>>> sorted(list1,key = lambda list1: list1[0])
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]
>>> sorted(list1,key = lambda list1: list1[1])
[('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
(3)用reverse排序
<span style="white-space:pre"> </span>>>> sorted(list1,reverse = True)
[('sara', 80), ('mary', 90), ('lily', 95), ('david', 90)]
(4)用operator.itemgetter函式排序
>>> from operator import itemgetter
>>> sorted(list1, key=itemgetter(1))
[('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
>>> sorted(list1, key=itemgetter(0))
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]
介紹operator.itemgetter函式
<span style="white-space:pre"> </span>>>> import operator
>>> a = [1,2,3]
>>> b = operator.itemgetter(0)
>>> b(a)
1
operator.itemgetter函式獲取的不是值,而是定義了一個函式。
(5)多級排序
>>> sorted(list1, key=itemgetter(0,1))
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]