1. 程式人生 > >leetcode 679. 24 Game 4個數加減乘除得到24 + 24點遊戲 + 暴力求解

leetcode 679. 24 Game 4個數加減乘除得到24 + 24點遊戲 + 暴力求解

You have 4 cards each containing a number from 1 to 9. You need to judge whether they could operated through *, /, +, -, (, ) to get the value of 24.

Example 1:
Input: [4, 1, 8, 7]
Output: True
Explanation: (8-4) * (7-1) = 24
Example 2:
Input: [1, 2, 1, 2]
Output: False
Note:
The division operator / represents real division, not integer division. For example, 4 / (1 - 2/3) = 12.
Every operation done is between two numbers. In particular, we cannot use - as a unary operator. For example, with [1, 1, 1, 1] as input, the expression -1 - 1 - 1 - 1 is not allowed.
You cannot concatenate numbers together. For example, if the input is [1, 2, 1, 2], we cannot write this as 12 + 12.

本題題意很簡單,最笨的方法就是直接考慮所有的情況

這道題值得反思,使用暴力求解還是不錯的

需要注意的是最後兩個數再多運算的時候設定了一個精度誤差

程式碼如下:

#include <iostream>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <string>
#include <climits>
#include <algorithm>
#include <sstream>
#include <functional> #include <bitset> #include <numeric> #include <cmath> #include <regex> using namespace std; class Solution { public: bool judgePoint24(vector<int>& nums) { sort(nums.begin(), nums.end()); do { if
(valid(nums)) return true; } while (next_permutation(nums.begin(), nums.end())); return false; } bool valid(vector<int>& nums) { double a = nums[0], b = nums[1], c = nums[2], d = nums[3]; if (valid(a + b, c, d) || valid(a - b, c, d) || valid(a*b, c, d) || b != 0 && valid(a / b, c, d)) return true; if (valid(a, b + c, d) || valid(a, b - c, d) || valid(a, b*c, d) || c != 0 && valid(a, b / c, d)) return true; if (valid(a, b, c + d) || valid(a, b, c - d) || valid(a, b, c*d) || d != 0 && valid(a, b, c / d)) return true; return false; } bool valid(double a, double b, double c) { if (valid(a + b, c) || valid(a - b, c) || valid(a*b, c) || b != 0 && valid(a / b, c)) return true; if (valid(a, b + c) || valid(a, b - c) || valid(a, b*c) || c != 0 && valid(a, b / c)) return true; return false; } bool valid(double a, double b) { if (abs(a + b - 24.0) < 0.0001 || abs(a - b - 24.0) < 0.0001 || abs(a*b - 24.0) < 0.0001 || b!= 0 && abs(a / b - 24.0) < 0.0001) return true; return false; } };