java 解析json, 帶轉義字元的json
阿新 • • 發佈:2019-02-09
一:解析普通json
1:不帶轉化字元
格式{"type":"ONLINE_SHIPS","message":{"currentTime":1400077615368,"direction":0,"id":1,"latitude":29.5506,"longitude":106.6466}}
JSONObject jsonObject = new JSONObject(jsonstr).getJSONObject("message"); System.out.println("currentTime:"+jsonObject.get("currentTime")); System.out.println("direction:"+jsonObject.get("direction")); System.out.println("latitude:"+jsonObject.get("latitude")); System.out.println("longitude:"+jsonObject.get("longitude"));
jsonarray
JSONObject jo = ja.getJSONArray("cargoList").getJSONObject(0);
2:帶轉義字元的json格式
{"type":"ONLINE_SHIPS","message":"{\"currentTime\":1400077615368,\"direction\":0,\"id\":1,\"latitude\":29.5506,\"longitude\":106.6466}"}
其實也很簡單,先把它轉化成字串就可以了
JSONObject jsonObject = new JSONObject(jsonstr); //先通過字串的方式得到,轉義字元自然會被轉化掉 String jsonstrtemp = jsonObject.getString("message"); System.out.println("message:"+jsonstrtemp); jsonObject = new JSONObject(jsonstrtemp); System.out.println("currentTime:"+jsonObject.get("currentTime")); System.out.println("direction:"+jsonObject.get("direction")); System.out.println("latitude:"+jsonObject.get("latitude")); System.out.println("longitude:"+jsonObject.get("longitude"));
二:遍歷Json物件
JSONObject ports = ja.getJSONObject("ports");
Iterator<String> keys = ports.keys();
while(keys.hasNext()){
String key=keys.next();
String value = ports.getString(key);
}