1. 程式人生 > >DOS下面關於精確延時1ms的函式(理論上可以非常精確延時到10微妙級別)

DOS下面關於精確延時1ms的函式(理論上可以非常精確延時到10微妙級別)

在微軟的MSC7.0以及MSVC1.52下面都沒有Borland C++的精確延時函式:delay(經過測試可以非常精確的延時到1ms)
同時看了一下計時器的相關內容,自己寫了一個精確延時函式,但不敢保證在所有的電腦上都可以精確延時
原始碼:
/***
*void xdelay(unsigned int ms)
*
*Purpose:
*    Make an exactly millisecond delay
*
*Entry:
*    unsigned int ms  - The delay time (millisecond)
*
*Exit:
*   void
*
*Exceptions:
*    Note:
*       .This function was created by Denny at Jun/26/2008
*       .Dongguan Siliten Electronics CO., LTD.
*       .The timer frequency is 1193180Hz
*       .The timer counter is 16bits, so only elapsed 55ms for/
*        counter a circle.
*
*******************************************************************************/
void xdelay(unsigned int ms)
{
    unsigned int base_counter;
    unsigned int circle;
    unsigned int counter;
    unsigned int last_counter;
    unsigned long end;
    unsigned long cur;

    disable();
    //outportb(0x43, 0x30);
    base_counter = inportb(0x40);
    base_counter += inportb(0x40)<<8;
    enable();
    circle = 0;
    last_counter = 0;
    end = (unsigned long)ms*1193;
    cur = 0;
    while (end > cur)
    {
        disable();
        counter = inportb(0x40);
        counter += inportb(0x40)<<8;
        enable();
        counter = base_counter - counter;
        if (counter-last_counter > 50)      // Illegal data
        {
            last_counter = counter;
            continue;
        }
        if ( (counter < last_counter) && (last_counter > 65000) && (counter < (65536-65000)) )
            circle++;
        cur = ((unsigned long)circle<<16) + counter;
        //printf("base:%u|cir:%u|cnt:%u|last:%u|end:%lu|cur:%lu/n", base_counter, circle, counter, last_counter, end, cur);
        last_counter = counter;
    }
}

下面是測試程式:
        ClrScr();
        for (i = 0; i < 5; i++)
        {
            printf("delay(1000):%d/r/n", i);
            for (j = 0; j < 1; j++)
                delay(1000);
        }
        for (i = 0; i < 5; i++)
        {
            printf("delay(100):%d/r/n", i);
            for (j = 0; j < 10; j++)
                delay(100);
        }
        for (i = 0; i < 5; i++)
        {
            printf("delay(10):%d/r/n", i);
            for (j = 0; j < 100; j++)
                delay(10);
        }
        for (i = 0; i < 5; i++)
        {
            printf("delay(1):%d/r/n", i);
            for (j = 0; j < 1000; j++)
                delay(1);
        }