1. 程式人生 > >C++ 指標的偏移 The offset of a pointer in C++

C++ 指標的偏移 The offset of a pointer in C++

A problem from my friend, what's the result of the following code:

class str{
public:
  int x;
  char s[0];
};

class foo{
public:
  str * p;
};
int main() {
  foo f = {0};
  str* p1 = NULL;
  if (f.p->s){
    printf("%d\n", f.p->s);
  }
  return 0;
}

This sentence sets p to NULL:
  foo f = {0};
f.p is a pointer of str, so f.p is an offset. I.e., f.p->s = base address + 4 So the result is 4