#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<sstream>
#include<algorithm>
#include<queue>
#include<deque>
#include<iomanip>
#include<vector>
#include<cmath>
#include<map>
#include<stack>
#include
 
<set>
#include<fstream>
#include<memory>
#include<list>
#include<string>
using namespace std;
typedef long long LL;
typedef unsigned long long ULL;
#define MAXN 100001
#define L 31
#define INF 1000000009
#define eps 0.00000001
struct node
{
    LL l, r, data;
}T[MAXN*4+10];
LL n,a[MAXN];
LL Query(LL p, LL k)
{
    
 
if (T[p].l == T[p].r)
        return T[p].data;
    LL mid = (T[p].l + T[p].r) >> 1;
    LL sum = T[p].data;
    if (k <= mid)
        sum += Query(p << 1, k);
    else
        sum += Query(p << 1 | 1, k);
    return sum;
}
void Build(LL p, LL l, LL r)
{
    T[p].l = l, T[p].r = r, T[p].data = 0
 
;
    if (l == r)
    {
        T[p].data = a[l];
        return;
    }
    LL mid = (l + r) >> 1;
    Build(p << 1, l, mid);
    Build(p <<1 | 1, mid + 1, r);
}
void Insert(LL p, LL l, LL r, LL num)
{
    //cout << p << ‘ ‘ << l << ‘ ‘ << r << ‘ ‘ << num << endl;
    if (l <= T[p].l&&r >= T[p].r)
    {
        T[p].data += num;
        return;
    }
    LL mid = (T[p].l + T[p].r) / 2;
    if (r <= mid)
        Insert(p << 1, l, r, num);
    else if (l > mid)
        Insert(p << 1 | 1, l, r, num);
    else
    {
        Insert(p << 1, l, mid, num);
        Insert(p << 1 | 1, mid + 1, r, num);
    }
}
int main()
{
    while (scanf("%lld", &n), n)
    {
        LL t1, t2;
        memset(a, 0, sizeof(a));
        Build(1, 1, n);
        for (LL i = 1; i <= n; i++)
        {
            scanf("%lld%lld", &t1, &t2);
            Insert(1, t1, t2, 1);
        }
        for (LL i = 1; i <= n; i++)
        {
            if (i>1) printf(" ");
            printf("%lld", Query(1, i));
        }
        printf("\n");
    }
    return 0;
}

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Color the ball Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 19857 Accepted Submission(s): 9901 Problem Description N個氣球排成一排，從左到右依次編號為1,2,3....N.每次給定2個整數a b(a <= b),lele便為騎上他的“小飛鴿"牌電動車從氣球a開始到氣球b依次給每個氣球塗一次顏色。但是N次以後lele已經忘記了第I個氣球已經塗過幾次顏色了，你能幫他算出每個氣球被塗過幾次顏色嗎？ Input 每個測試實例第一行為一個整數N,(N <= 100000).接下來的N行，每行包括2個整數a b(1 <= a <= b <= N)。 當N = 0，輸入結束。 Output 每個測試實例輸出一行，包括N個整數，第I個數代表第I個氣球總共被塗色的次數。 Sample Input 3 1 1 2 2 3 3 3 1 1 1 2 1 3 0 Sample Output 1 1 1 3 2 1 Author 8600

Color the ball 線段樹 區間更新但點查詢