洛谷 P1596 [USACO10OCT]湖計數Lake Counting 題解
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題目鏈接:https://www.luogu.org/problem/show?pid=1596
題目描述
Due to recent rains, water has pooled in various places in Farmer John‘s field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water (‘W‘) or dry land (‘.‘). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors. Given a diagram of Farmer John‘s field, determine how many ponds he has.
由於近期的降雨,雨水匯集在農民約翰的田地不同的地方。我們用一個NxM(1<=N<=100;1<=M<=100)網格圖表示。每個網格中有水(‘W‘) 或是旱地(‘.‘)。一個網格與其周圍的八個網格相連,而一組相連的網格視為一個水坑。約翰想弄清楚他的田地已經形成了多少水坑。給出約翰田地的示意圖,確定當中有多少水坑。
輸入輸出格式
輸入格式:Line 1: Two space-separated integers: N and M * Lines 2..N+1: M characters per line representing one row of Farmer John‘s field. Each character is either ‘W‘ or ‘.‘. The characters do not have spaces between them.
第1行:兩個空格隔開的整數:N 和 M 第2行到第N+1行:每行M個字符,每個字符是‘W‘或‘.‘,它們表示網格圖中的一排。字符之間沒有空格。
輸出格式:Line 1: The number of ponds in Farmer John‘s field.
一行:水坑的數量
輸入輸出樣例
輸入樣例#1:10 12 W........WW. .WWW.....WWW ....WW...WW. .........WW. .........W.. ..W......W.. .W.W.....WW. W.W.W.....W. .W.W......W. ..W.......W.
3
分析:
深度優先搜索。
AC代碼:
1 #include<iostream> 2 #include<cstdio> 3 #include<cmath> 4 #include<algorithm> 5 6 using namespace std; 7 char mp[110][110]; 8 int m,n,ans = 0; 9 void dfs(int x,int y) 10 { 11 mp[x][y] = ‘.‘; 12 //通過將水坑標記為旱地,避免再次遍歷 13 for(int i = -1;i <= 1;i ++) 14 for(int j = -1;j <= 1;j ++) 15 { 16 int nx = x + i; 17 int ny = y + j; 18 if(nx > 0 && nx <= n && ny > 0 && ny <= m && mp[nx][ny] == ‘W‘) 19 dfs(nx,ny); 20 } 21 return; 22 } 23 24 int main() 25 { 26 scanf("%d%d",&n,&m); 27 for(int i = 1;i <= n;i ++) 28 scanf("%s",mp[i] + 1); 29 for(int i = 1;i <= n;i ++) 30 for(int j = 1;j <= m;j ++) 31 { 32 if(mp[i][j] == ‘W‘) 33 dfs(i,j),ans ++; 34 } 35 printf("%d",ans); 36 return 0; 37 }
洛谷 P1596 [USACO10OCT]湖計數Lake Counting 題解