# 作業5：多級菜單
#   ● 三級菜單，省、市、縣、公司，要求程序啟動後，允許用戶依次選擇進入各子菜單
#   ● 可以在任意一級菜單返回上級菜單，也可以退出程序
#   ● 所需新知識點：列表、字典
#
# 思路：
# 先創字典，字典三層嵌套
#逐層提取key字段，
#先不管各種可能，把主程序寫好，即各種選擇都是好好的情況下能實現的功能，再補充各種可能
#這個地方其實是重點考察while循環裏面的continue和break
#出於程序簡化，沒有考慮輸入數字超範圍、輸入的不是數字、q、b三者以外的情況

dict1 ={
        "省1":{
            "市11":{
                
 
"縣111":{
                    "公司1111:{}",
                    "公司1112:{}"
                },
                "縣112":{
                    "公司1121:{}",
                    "公司1122:{}"
                }
            },
            "市12":{
                "縣121":{
                    "公司1211:{}",
                    
 
"公司1212:{}"
                },
                "縣122":{
                    "公司1221:{}",
                    "公司1222:{}"
                }
            },
            "市13":{
                "縣131":{},"縣132":{}
            }
        },
        "省2":{
            "市21":{
                "縣211":{},"縣212
 
":{}
            },
            "市22":{
                "縣221":{},"縣222":{}
            },
            "市23":{
                "縣231":{},"縣232":{}
            }
        },
        "省3":{
            "市31":{
                "縣311":{},"縣312":{}
            },
            "市32":{
                "縣321":{},"縣222":{}
            },
            "市33":{
                "縣331":{},"縣332":{}
            }
        }
}

judge = True

while judge:
    list1 = list(dict1.keys())
    list1.sort()
    print("The level_1 menu:")
    for index,item in enumerate(list1):
        print(index,item)
    choice1 = input("Please choose level_1:")
    if choice1.isdigit():
        choice1 = int(choice1)
        choice_key1 = list1[choice1]
        list2 = list(dict1.get(choice_key1))
        list2.sort()
        while judge:
            print("The level_2 menu:")
            for index, item in enumerate(list2):
                print(index, item)
            choice2 = input("Please choose level_2:")
            if choice2.isdigit():
                choice2 = int(choice2)
                choice_key2 = list2[choice2]
                list3 = list(dict1.get(choice_key1).get(choice_key2))
                list3.sort()
                while judge:
                    print("The level_3 menu:")
                    for index, item in enumerate(list3):
                        print(index, item)
                    choice3 = input("Please choose level_3:")
                    if choice3.isdigit():
                        choice3 = int(choice3)
                        choice_key3 = list3[choice3]
                        list4 = list(dict1.get(choice_key1).get(choice_key2).get(choice_key3))
                        list4.sort()
                        print("The level_4 menu:")
                        for index, item in enumerate(list4):
                            print(index, item)
                        choice4 = input("It‘s the last level,Please come back:")
                        if choice4 == "q":
                            # 判斷位置空後，可以連續跳出多個循環
                            judge = False
                            # 這裏是跳出了本while循環的所有循環
                            break
                        elif choice4 == "b":
                            # 這裏只是跳出了本while循環中的一次循環
                            continue
                    elif choice3 == "q":
                        judge = False
                        break
                    elif choice3 == "b":
                        break
            elif choice2 == "q":
                judge = False
                break
            elif choice2 == "b":
                break
    elif choice1 == "q" :#是q退出
        judge = False
    else:#不是q也不是數字，重新選
        print("Please choose the number.")

python作業5：多級菜單