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maximum-subarray 序列最大連續和 貪心

subarray span odin sin pub ive question more pid

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array[?2,1,?3,4,?1,2,1,?5,4],
the contiguous subarray[4,?1,2,1]has the largest sum =6.

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More practice:

If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

貪心算法,當連續和sum>0時,sum+=A[i],負責sum=A[i]
class Solution {
public:
    int maxSubArray(int A[], int n) {
        int max=A[0],sum=0;
        for(int i=0;i<n;++i)
        {
            if(sum<0)
                sum=A[i];
            else
                sum+=A[i];
            max=max<sum?sum:max;
        }
        
return max; } };

maximum-subarray 序列最大連續和 貪心