python leetcode 45. Jump Game II
cur，last分別表示當前這一步，上一步能到達的最大下標位置
- 如果當前下標i>last: 步數加1 更新last=cur
- 否則：更新cur
由於假設能到最後位置，所以省去了判斷是否能到。
class Solution:
def jump(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
n=len(nums)
cur=last=step=0
for i in range 相關推薦
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