1. 程式人生 > >微分方程求解

微分方程求解

1. 尤拉方法

通過計算:

  

求[a,b]上的初值問題 y'=f(t,y),y(a)=y0的近似解。

function E=euler(f,a,b,ya,M)
%Input  - f is the function entered  as a string 'f'
%       - a and b are the left and right end points
%       - ya is the initial condition y(a)
%       - M is the number of steps
%Output - E=[T' Y'] where T is the vector of abscissas and
% Y is the vector of ordinates h=(b-a)/M; Y=zeros(1,M+1); T=a:h:b; Y(1)=ya; for j=1:M Y(j+1)=Y(j+h*feval(f,T(j),Y(j))); end E=[T' Y']; end