561. Array Partition I - LeetCode

阿新 • • 發佈：2018-06-30

class urn src scrip problems 相加 arr for pair

Question

561. Array Partition I

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Solution

題目大意是，給的數組大小是2n，把數組分成n組，每組2個元素，每個組取最小值，這樣就能得到n個值，怎樣分組才能使這n個數相加最小。

思路：有點田忌賽馬的意思，肯定最大和第二大一組，取最小值即第二大的數，依次類推。。。這樣就需要排序，隔一個取一個。

Java實現：

public int arrayPairSum(int[] nums) {
    Arrays.sort(nums);
    int total = 0;
    for (int i=0; i<nums.length; i+=2) {
        total += nums[i];
    }
    return 
 total;
}

561. Array Partition I - LeetCode

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561. Array Partition I - LeetCode

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