LeetCode.561. Array Partition I
題目的大意為給定一個長度為2n的陣列，把陣列分為n對，使從1到n的min(ai,aj)的總和最大。
比如：
Input: [1,4,3,2]
Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).拿到這道題，發現排序後比較好解決。
可以發現排序後相鄰兩個元素分組，把奇數位置的元素相加即為所求。
public int arrayPairSum(int[] nums) { Arrays.sort(nums); int sum = 0; for (int i = 0; i < nums.length; i += 2) { sum += nums[i]; } return sum; }
也有其他更好的方法，正在探索當中。
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