This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.

    Input
    Each line will contain two integers A and B. Process to end of file.

    Output
    For each case, if(A+B)%86=0,output yes in one line,else output no in one line.

    Sample Input
    1 1
 

8600 8600

    Sample Output
    no
    yes

題目說明：
輸入兩個數A和B，判斷他們的和能否被86整除，若可以，則輸出“yes”，否則輸出“no”。
程式說明：
用cin>>a>>b作為while（）的引數，可以實現多次輸入資料的要求，while（）函式內執行if判斷語句，看A+B能否被86整除。
程式實現：

#include <iostream>
using namespace std;
int main()
{
    int a, b;
 while (cin >> a >> b)
 

 {
  if ((a+b)%86)
   cout << "no" << endl;
  else
   cout << "yes" << endl;
  }
}