1. 程式人生 > >BZOJ P1296 [SCOI2009]粉刷匠【區間DP】【揹包DP】

BZOJ P1296 [SCOI2009]粉刷匠【區間DP】【揹包DP】

#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define ll long long
#define rep(i,x,y) for(ll i=(x);i<=(y);i++)
#define repl(i,x,y) for(ll i=(x);i<(y);i++)
#define repd(i,x,y) for(ll i=(x);i>=(y);i--)
using namespace
std; const int N=1e2+5; const int M=3e3+5; ll n,m,t,ans,sum[N],f1[N][M],f2[N][M]; inline ll read() { ll x=0;char ch=getchar();bool f=0; while(ch>'9'||ch<'0'){if(ch=='-')f=1;ch=getchar();} while(ch>='0'&&ch<='9'){x=(x<<1)+(x<<3)+ch-'0';ch=getchar();} return
f?-x:x; } int main() { n=read(),m=read(),t=read(); rep(k,1,n) { char ch[N]; scanf("%s",ch+1); rep(i,1,m) sum[i]=sum[i-1]+(ch[i]=='1'); rep(i,1,m) rep(j,1,m) { f1[j][i]=0; rep(mid,0,j-1) f1[j][i]=max(f1[j][i],f1[mid][i-1]+max(sum[j]-sum[mid],j-mid-sum[j]+sum[mid])); } rep(i,1
,t) rep(j,1,min(i,t)) f2[k][i]=max(f2[k][i],f2[k-1][i-j]+f1[m][j]); } rep(i,1,t) ans=max(ans,f2[n][i]); printf("%lld",ans); return 0; }