Median of two Sorted Arrays

Description:

There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays.

Example Given A=[1,2,3,4,5,6] and B=[2,3,4,5], the median is 3.5.

Given A=[1,2,3] and B=[4,5], the median is 3.

Challenge The overall run time complexity should be O(log (m+n)).

Code：

class Solution:
    """
    @param: A: An integer array
    @param: B: An integer array
    @return: a double whose format is *.5 or *.0
    """
    def findMedianSortedArrays(self, A, B):
        # write your code here
        le = len(A)+len(B)
        if le%2==0:
            print('even')
            print
 
('left', self.findK(A,B,int(le/2)))
            print('right', self.findK(A,B,int(le/2)+1))
            return (self.findK(A,B,int(le/2))+self.findK(A,B,int(le/2)+1))/2
        else:
            return self.findK(A,B,int(le/2)+1)
        
    def findK(self, A, B, k):
        la, lb = len(A), len(B)
        halfk =
 
 int(k/2)
        print('halfk', k, halfk)
        if la<lb:
            return self.findK(B, A, k)
        if lb == 0:
            return A[k-1]
        if k==1:
            return min(A[0], B[0])
        ib = min(lb, halfk) if halfk!=0 else 1
        ia = k-ib if k-ib!=0 else 1
        print('ia,ib',ia,ib)
        if B[ib-1]==A[ia-1]:
            return B[ib-1]
        if B[ib-1]<A[ia-1]:
            
            if lb==ib:
                return A[ia-1]
            return self.findK(A[:ia], B[ib:], ia)
        if B[ib-1]>A[ia-1]:
            if la==ia:
                return B[ib-1]
            return self.findK(A[ia:], B[:ib], ib)