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leetcode之Find Minimum in Rotated Sorted Array II

問題描述如下:

Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2

).

Find the minimum element.

The array may contain duplicates.

問題連結

cpp程式碼如下:

class Solution {
public:
    int findMin(vector<int> &num) {
        if(num.size()==0)return -1;
        int l=0,h=num.size()-1;
        while(num[l]>=num[h]){
            if(l+1==h)
                return num[h];
            int m=l+(h-l)/2;
            if(num[l]==num[m]&&num[m]==num[h]){
                int min_=num[l];
                for(int i=l+1;i<=h;++i)
                    if(min_>num[i])min_=num[i];
                return min_;
            }else if(num[l]<=num[m]){
                l=m;
            }else h=m;
        }
        return num[l];
    }
};