Problem Description You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’ to be ‘2’, or leave the ‘1’ there. Surly, you may get many different results. For example, given 1111 , you can get 1111, 121, 112,211,22. Now, your work is to find the total number of result you can get.

Input The first line is a number n refers to the number of test cases. Then n lines follows, each line has a string made up of ‘1’ . The maximum length of the sequence is 200.

Output The output contain n lines, each line output the number of result you can get .

Sample Input 3 1 11 11111

//做完fibonacci和大菲波數就能懂了 

#include<stdio.h>
#include<string.h>
char s[210];
int num[210][1010];
int len;
int main()
{
    int n;
    int i,j;
    memset(num,0,sizeof(num));
    num[1][0]=1;
    num[2][0]=2;
    //int k,l;
    //l=0;
    for(i=3;i<210;i++)
    {
        //k=0;
        for(j=0;j<1000;j++)
        {
            //l=k+num[i-1][j]+num[i-2][j];
            //num[i][j]=l%10;
            //k=l/10;
            num[i][j]+=num[i-1][j]+num[i-2][j];//'+='把我坑慘了 ,我寫成=
            if(num[i][j]>=10)
            {
            	num[i][j]-=10;
            	num[i][j+1]+=1;
            }
        }           
    }
    scanf("%d",&n);
    getchar();
    while(n--)
    {    
        scanf("%s",s);
        len=strlen(s);     
		for(i=1000-1;i>0&&num[len][i]==0;--i)//清零 
		;
		  
        for(;i>=0;i--)
           printf("%d",num[len][i]);
        printf("\n");
    }
    return 0;
}