【鏈接】 我是鏈接,點我呀:)
【題意】

讓你從1..n這n個數字中
選出來k個不相交的長度為m的區間
然後這個k個區間的和最大
求出這k個區間的和的最大值

【題解】

設dp[i][j]表示前i個數字已經選出了j個區間的最大值
看看是以當前位置為結尾選擇一個區間,還是這個位置不包括在任何一個區間裏.
分這兩種情況轉移就好

【代碼】

import java.io.*;
import java.util.*;

public class Main {
    
    
    static InputReader in;
    static PrintWriter out;
        
    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }
    
    static int N = 5000;
    static class Task{
        
        int n,m,k;
        int a[];
        long sum[];
        long dp[][];
        
        long get_sum(int l,int r) {
            return sum[r]-sum[l-1];
        }
        
        public void solve(InputReader in,PrintWriter out) {
            n = in.nextInt();m = in.nextInt();k = in.nextInt();
            a = new int[N+10];
            sum = new long[N+10];
            dp = new long[N+10][N+10];
            
            for (int i = 1;i <= n;i++) {
                a[i] = in.nextInt();
            }
            for (int i = 1;i <= n;i++) sum[i]=sum[i-1]+a[i];
            long ans = 0;
            dp[0][0] = 0;
            for (int i = 1;i <= n;i++)
                for (int j = 0;j <= Math.min(k, i);j++) {
                    if (j==0) {
                        dp[i][j] = Math.max(dp[i][j], dp[i-1][j]);
                    }else {
                        if (i-m>=0) {
                            dp[i][j] = Math.max(dp[i][j], dp[i-m][j-1]+get_sum(i-m+1,i));
                            dp[i][j] = Math.max(dp[i][j], dp[i-1][j]);
                        }
                    }
                    ans = Math.max(ans, dp[i][j]);
                }
            out.println(ans);
        }
    }

    

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;
        
        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }
        
        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}
 

【Codeforces 467C】George and Job