Leetcode 389. Find the Difference

阿新 • • 發佈：2019-04-05

return diff sel 回來字符串 tco object leet ret

多了一個字母,就兩個字符串一減就得到多的那個.

但是字符串不能直接相減,所以就轉成數字再減,最後再轉回來.

class Solution(object):
    def findTheDifference(self, s, t):
        return chr(sum(map(ord,t))-sum(map(ord,s)))

Leetcode 389. Find the Difference

python leetcode 389. Find the Difference

class Solution: def findTheDifference(self, s, t): """ :type s: str :type t: str :rtype: str """

[leetcode]389. Find the Difference

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string&nb

leetcode 389 Find the Difference 找不同 python 多種思路，最簡程式碼（collections.Counter()構建字典）

class Solution: def findTheDifference(self, s, t): """ :type s: str :type

Leetcode 389. Find the Difference

return diff sel 回來字符串 tco object leet ret 多了一個字母,就兩個字符串一減就得到多的那個. 但是字符串不能直接相減,所以就轉成數字再減,最後再轉回來. class Solution(object): def fin

[LeetCode&Python] Problem 389. Find the Difference

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string

LeetCode-136. Single Number 389. Find the Difference

136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Concept If we ta

*389. Find the Difference (string + map(26)) read problems carefully

star lse ger shuff position add letters strings per Given two strings s and t which consist of only lowercase letters. String t is genera

389. Find the Difference 用list的方法strip()隔斷字串判斷list長度來確定差別字元

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string&

LeetCode-Find the Difference

Description： Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s

leetcode Find the Difference

Find the Difference 思路：建立兩個map 統計每個字串出現的次數，如果一個字串不包含另一個的字串，返回字元，或者，兩個字元出現的字數不相同，返回字元。 public static void main(String[] args) { String s = "abcd"

LeetCode演算法題-Find the Difference（Java實現-五種解法）

這是悅樂書的第214次更新，第227篇原創 01 看題和準備今天介紹的是LeetCode演算法題中Easy級別的第82題（順位題號是389）。給定兩個字串s和t，它們只包含小寫字母。字串t由隨機混洗字串s生成，然後在隨機位置再新增一個字母。找到t中新增的字母。例如：輸入：s =“abcd”, t

[LeetCode] Find the Difference 尋找不同

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a

LeetCode 287. Find the Duplicate Number （找到重復的數字）

ant pre ast web integer lan algorithm xtra 理論 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclus

Leetcode 277: Find the Celebrity

style orm cal call leetcode ask eth num help Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may

LeetCode 287. Find the Duplicate Number

find 由於 ray all turn num pre n-1 DDU 解法一：類似 LeetCode 442. Find All Duplicates in an Array，由於元素是1~n，因此每個元素的值-1（映射到0~n-1）就可以直接當做下標。 cl

[LeetCode] 287. Find the Duplicate Number 尋找重復數

blank arc modify ini lba read href use rep Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive

[LeetCode] 287. Find the Duplicate Number

etc int 一個數空間 ont slow i++ for clu Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prov

[leetcode]287. Find the Duplicate Number

[leetcode]287. Find the Duplicate Number Analysis fighting!!!—— [每天刷題並不難0.0] Given an array nums containing n + 1 integers where e

[LeetCode] 277. Find the Celebrity

Problem Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may exist one celebrity. The definit

名人問題演算法解析與Python 實現 O(n) 複雜度（以Leetcode 277. Find the Celebrity為例）

1. 題目描述 Problem Description Leetcode 277. Find the Celebrity Suppose you are at a party with n people (labeled from 0 to n -

Leetcode 389. Find the Difference

相關推薦