1. 程式人生 > >九度OJ 1208: 10進位制 VS 2進位制

九度OJ 1208: 10進位制 VS 2進位制

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
  
void swap(int *p, int *q)
{
    int temp;
    temp = *p;
    *p = *q;
    *q = temp;
}
  
void reverse(int arr[], int left, int right)
{
    int i;
    for(i = left; i <= (left+right)/2; i++)
        swap(arr + i, arr + left + right - i);
}
 
/*將m進位制的大數X所在陣列arr_m[]轉換為n進位制陣列arr_n[],並求arr_n[]陣列的長度*/
void m_to_n(int arr_m[], int arr_n[], int m, int n, int m_len, int *pn)  
{  
    *pn = 0;                              //arr_n陣列長度清0  
    int i, j;  
    for(i = 0; i < m_len;)                //不斷地將X除以n,並將餘數存入arr_n[],直到X為0  
    {  
        int r = 0;                        //餘數清0  
        for(j = i; j < m_len; j++)        //將大整數除以n,餘數存入r  
        {  
            int temp = arr_m[j] + m * r;  
            r = temp % n;  
            arr_m[j] = temp / n;  
        }  
        arr_n[(*pn)++] = r;               //將餘數r對應的字元寫入n陣列  
        while(arr_m[i] == 0)              //略過為0的高位  
            i++;  
    }  
    reverse(arr_n, 0, *pn - 1);           //將arr_n[]逆置   
}  
  
int main()
{
    char s[1010];
    int dec[1010] = {0};
    int bin[4000] = {0};
    while(gets(s) != NULL)
    {
        int dec_len = strlen(s);
        int bin_len = 0;
        int *pd = &dec_len;
        int *pb = &bin_len;
        int i;
        for(i = 0; i < dec_len; i++)        //將讀入的字串轉換為整數陣列
            dec[i] = s[i] - '0';
        m_to_n(dec, bin, 10, 2, dec_len, pb);
        reverse(bin, 0, bin_len - 1);
        m_to_n(bin, dec, 2, 10, bin_len, pd);
        for(i = 0; i < dec_len; i++)
            printf("%d", dec[i]);
        printf("\n");
    }
    //system("pause");
    return 0;
}
/**************************************************************
    Problem: 1208
    User: superlc320
    Language: C++
    Result: Accepted
    Time:50 ms
    Memory:1020 kb
****************************************************************/