OIBH杯第三次普及組模擬賽T3 最大約數和
阿新 • • 發佈:2019-01-10
T3:
題解:
先預處理出每個數的因數和,然後在進行DP
轉移方程:f[i,j]表示到數字i,總和為j的最大因數和,f[i,j]=max(f[i-1,j-i]+a[i],f[i-1,j]);
參考程式:
var n,i,j,t:longint;
a:array[1..1000]of longint;
f:array[0..1000,0..1000]of longint;
function max(x,y:longint):longint;
begin
if x>y then exit(x) else exit(y);
end;
begin
assign(input,'maxsum.in');reset(input);
assign(output,'maxsum.out');rewrite(output);
readln(n);
for i:=2 to n do
for j:=1 to i-1 do
if i mod j=0 then a[i]:=a[i]+j;
for i:=1 to n do
for j:=0 to n do
if j-i>=0 then f[i,j]:=max(f[i-1,j-i]+a[i],f[i-1,j]) else
f[i,j]:=f[i-1,j];
writeln(f[n,n]);
close(input);close(output);
end .